Plot only equilateral triangles

15 次查看(过去 30 天)
Plot random 10 triangles and plot only almost equilateral triangles. Check whether the three edges differ by less than a chosen small constant, for example e = 0.01. I have drawn the random triangles but I need to plot only equilateral triangles. So far, I get any random triangles including obtuse, acute and equilateral triangles.
  3 个评论
Mayur Deogade
Mayur Deogade 2020-9-4
编辑:Mayur Deogade 2020-9-4

figure, hold on

for i=1:10 Fill(rand(3,1), rand(3,1), rand(1,3))

End

Axis([0 1 0 1])

Axis square off

Mayur Deogade
Mayur Deogade 2020-9-4
Here, I am able to plot 10 random triangles but I need to plot only triangles which are nearly equilateral

请先登录,再进行评论。

采纳的回答

Asad (Mehrzad) Khoddam
figure, hold on
e = 0.01;
i=0;
while i<= 10
x = rand(3,1);
y = rand(3,1);
c = rand(3,1);
L1 = sqrt((x(2)-x(1)).^2 + (y(2) - y(1)).^2);
L2 = sqrt((x(3)-x(1)).^2 + (y(3) - y(1)).^2);
L3 = sqrt((x(3)-x(2)).^2 + (y(3) - y(2)).^2);
L = sort([L1, L2, L3]);
if L(2)-L(1) < e && L(3) - L(2) <e && L(3)-L(1) < e
i = i + 1;
fill(x,y,c)
end
end
axis([0 1 0 1])
axis square off

更多回答(2 个)

Alan Stevens
Alan Stevens 2020-9-5
Here's an alternative approach:
e = 0.01;
for i = 1:10
xc = rand(1); yc = rand(1);
r = rand(1);
while r < e/sqrt(3)
r = rand(1);
end
theta1 = 2*pi*rand(1);
theta = [theta1;
theta1 + 2*pi/3;
theta1 + 4*pi/3];
x = xc + r*cos(theta);
y = yc + r*sin(theta);
plot([x; x(1)],[y; y(1)])
hold on
end
axis equal off

Asad (Mehrzad) Khoddam
figure, hold on
e = 0.0001;
i=0;
while i<= 10
x = rand(3,1);
y = rand(3,1);
c =rand(3,1);
L1 = sqrt((x(2)-x(1)).^2 + (y(2) - y(1)).^2);
L2 = sqrt((x(3)-x(1)).^2 + (y(3) - y(1)).^2);
L3 = sqrt((x(3)-x(2)).^2 + (y(3) - y(2)).^2);
L = sort([L1, L2, L3]);
if L(2)-L(1) < e || L(3) - L(2) <e
i = i + 1;
fill(rand(3,1), rand(3,1), rand(1,3))
end
end
axis([0 1 0 1])
axis square off

类别

Help CenterFile Exchange 中查找有关 Descriptive Statistics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by