Hello! I need some help solving linear equations for the coefficients
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This is the question:
Liz buys three apples, a dozen bananas, and one cantaloupe for $2.36.
Bob buys a dozen apples and two cantaloupe for $5.26.
Carol buys two bananas and three cantaloupe for $2.77.
How much do single pieces of each fruit cost?
This is my work so far:
%Set the variables to be used in the problem.
syms x y z
%Input the equations given in the problem.
Equation_1 = input('Input the given equation. To input the total amount use "==". ')
Equation_2 = input('Input the given equation. To input the total amount use "==". ')
Equation_3 = input('Input the given equation. To input the total amount use "==". ')
%Transform the linear equation into a matrix form
[A, B] = equationToMatrix ([Equation_1, Equation_2, Equation_3], [x, y, z])
I tried running it, but it errors when I put the equation. Thanks in advance!
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回答(3 个)
Álvaro
2023-11-30
编辑:Image Analyst
2023-11-30
Hi, I tried the following code (I do not know why, but one of the prices is less than zero)
x = [ 3 12 1; 0 12 2; 0 2 3];
y = [2.36; 5.26; 2.77];
v = linsolve(x,y)
Image Analyst
2023-11-30
@Álvaro you should have done it like this:
% Liz buys three apples, a dozen bananas, and one cantaloupe for $2.36.
% Bob buys a dozen apples and two cantaloupe for $5.26.
% Carol buys two bananas and three cantaloupe for $2.77.
% How much do single pieces of each fruit cost?
% 2.36 = 3 * a + 12 * b + c
% 5.26 = 12 * a + 0 * b + 2 * c
% 2.77 = 0 * a + 2 * b + 3 * c
% totals = quantities * individualPrices
% Create arrays that describe the set of linear equations:
totals = [2.36; 5.26; 2.77]
quantities = [3, 12, 1;
12, 0, 2;
0, 2, 3]
individualPrices = linsolve(quantities,totals)
% Double check:
totalsCheck = quantities * individualPrices
另请参阅
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