recursive function to calculate Max number.
显示 更早的评论
function mx=recursive_max(v)
if numel(v)==1
mx=v;
end
if numel(v)>1
mx= recursive_max(1);
end
this much i've got so far.
Please help with this code.
1 个评论
JAYANTHI SANKARALINGAM
2020-9-20
When we use this,it shows error as
incorrectRandom vector Variable mx has an incorrect value. Test failed using v =[ 14 92 89 27 8 ]
采纳的回答
Urmish Haribhakti's general approach is quite good, with a few small changes it will work correctly:
function x = recmax(v)
if numel(v)<=1
x = v;
else
x = recmax(v(2:end));
if v(1)>x
x = v(1);
end
end
end
And tested:
>> recmax([28,2,6,1,999,8])
ans = 999
更多回答（5 个）
Mati Somp
2020-10-9
One more
function mx = recursive_max(v)
if length(v)==1
mx=v
else
if v(1)<=v(2)
v(1)=[]
else
v(2)=[]
end
mx=recursive_max(v)
end
1 个评论
xin yi leow
2021-1-25
This works for me and is easy to understand! if v(1) < v(2), we remove the first element, and if v(2)<v(1), we remove the v(2), that way we only keep the larger of the 2 elements in the vector. The last remaining element will naturally be the largest one.
Ameer Hamza
2020-9-9
编辑：Ameer Hamza
2020-9-10
Something like this:
function mx = recursive_max(v)
x = zeros(1, 2);
if numel(v) > 2
a = floor(numel(v)/2);
x(1) = recursive_max(v(1:a));
x(2) = recursive_max(v(a+1:end));
elseif numel(v) == 1
x = [v -inf];
else
x = v;
end
if x(1) > x(2)
mx = x(1);
else
mx = x(2);
end
end
I am not sure if this is an optimal algorithm.
2 个评论
Piyush Gupta
2020-9-10
编辑：Piyush Gupta
2020-9-10
can you explain the code....
Ameer Hamza
2020-9-10
It divides the input vector into two parts recursively. When the length of the divided vector reaches two during recursion, the recursion stops, and the function returns back the largest of the two elements.
JAYANTHI SANKARALINGAM
2020-9-20
0 个投票
Write a function called recursive_max that finds the maximum element in a vector without using loop or any built in functions.the sole output argument is the maximum value in the input vector.
Himalsha Dharmapala
2021-1-15
0 个投票
function output= recursive_max3(v)
if v(1,:)==0
output=v(1);
else
if v(end)>=v
output=v(end);
else
output= recursive_max3(v(1:end-1));
end
end
end
Welid Benchouche
2021-8-18
my solution to this assignment is
function mx = my_recursive_max(v)
% base case
if length(v) == 1
mx = v;
else
% recursive case
a = v(end);
b = v(1);
if a <= b
mx = b;
mx = my_recursive_max(v(1:end-1))
else
mx = a;
mx = my_recursive_max(v(2:end))
end
end
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