While loop keep running (logical with vector )
显示 更早的评论
Hi all,
My while loop running without stopping, I wanna it run until reach to logical function of a equal or smaller than 10. which should be any two numbers a=[6 3] or a=[6 6]
thanks,
clearvars;
clc;
a=[0 0];
while all(a)<=6
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
采纳的回答
Ameer Hamza
2020-9-10
编辑：Ameer Hamza
2020-9-10
Check this
clc;
a=[inf inf]; % start with all elemets > 6
while ~all(a <= 6)
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
4 个评论
Ali Tawfik
2020-9-10
Ameer Hamza
2020-9-10
There was a mistake in the while condition. Check the updated code.
Ali Tawfik
2020-9-10
Ameer Hamza
2020-9-10
I am glad to be of help! The other question seems to be a bit complicated to debug, but the main error is in the use of all() function. As you can see in my code, the comparison should be inside the all() function, not outside.
For example, instead of
all(x) > 1
you should write
all(x > 1)
更多回答（1 个）
BOB MATHEW SYJI
2020-9-10
0 个投票
I think replacing while with if solves the problem
clearvars;
clc;
a=[0 0];
if all(a)<=6
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
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