While loop keep running (logical with vector )
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Hi all,
My while loop running without stopping, I wanna it run until reach to logical function of a equal or smaller than 10. which should be any two numbers a=[6 3] or a=[6 6]
thanks,
clearvars;
clc;
a=[0 0];
while all(a)<=6
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
2 个评论
采纳的回答
Ameer Hamza
2020-9-10
编辑:Ameer Hamza
2020-9-10
Check this
clc;
a=[inf inf]; % start with all elemets > 6
while ~all(a <= 6)
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
4 个评论
Ameer Hamza
2020-9-10
I am glad to be of help! The other question seems to be a bit complicated to debug, but the main error is in the use of all() function. As you can see in my code, the comparison should be inside the all() function, not outside.
For example, instead of
all(x) > 1
you should write
all(x > 1)
更多回答(1 个)
BOB MATHEW SYJI
2020-9-10
I think replacing while with if solves the problem
clearvars;
clc;
a=[0 0];
if all(a)<=6
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
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