Cannot use besselh as function handle
显示 更早的评论
Hello everyone,
I need to convert a symbolic expression containing besselh functions to MATLAB function handle but I get an error message.
Here is a sample of code:
syms nu z
hankel = symfun(besselh(nu,z),[nu,z]) ;
F = matlabFunction(hankel(nu,z)) ;
It works well but if try to use the function F, I get this messsage:
Undefined function or variable 'besselH1'.
Indeed, the F function is defined as:
@(nu,z)besselH1(nu,z)
I use MATLAB R2019a.
What can I do?
2 个评论
Walter Roberson
2020-9-11
Sigh, yet another function that matlabFunction() messes up on :(
Johnes Ricardo
2020-11-5
编辑：Johnes Ricardo
2020-11-10
I have the same problem, I do not know whats happens, but I used [ besselj(n, x) + 1i*bessely(n, x) ] instead.
回答（1 个）
David Goodmanson
2020-9-11
0 个投票
Hi wbriand,
any reason you can't just define
F = @(nu,z) besselh(nu,1,z)
or
F = @(nu,z) besselh(nu,2,z)
whichever one you want?
1 个评论
Walter Roberson
2020-11-5
The problem is that if you have an expression in which besselh is one component, and you matlabFunction in order to generate code that can be used numerically, then matlabFunction messes up and generates a reference to a function that does not exist at the MATLAB level.
You could deliberately create a real function withthe Rogue name that interfaced back to besselh though.
类别
在 帮助中心 和 File Exchange 中查找有关 Linear Algebra 的更多信息
2020-11-10
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
