Cannot open file for reading when using system()

Question

Thomas Weaver 2020-9-11

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/592309-cannot-open-file-for-reading-when-using-system

编辑： Mario Malic 2020-9-11

I have two files in a directory, 'test01.model' and 'test02.model'. These files are used as input into a Windows executable program. My code uses the system command to run the .exe program with each file and obtain the results. As an example, I use the following code.

sysInput = 'C:\geopsypack-win10-3.3.1\bin\gpdc.exe test01.model'
[status, result] = system(sysInput, '-echo');

Everything works fine for 'test01.model.

When I change sysInput to:

sysInput = 'C:\geopsypack-win10-3.3.1\bin\gpdc.exe test02.model'

I get the following message: 'Cannot open file 'test02.model' for reading'.

If I use the ! command as follows

!C:\geopsypack-win10-3.3.1\bin\gpdc.exe < test02.model

The following is returned: 'The system cannot find the file specified.'

I have used the exist command as follows:

exist('C:\geopsypack-win10-3.3.1\bin\test02.model')

A value of 2 is returned, so the file does exist.

When I open up a poweshell in the directory where 'gpdc.exe' and 'test02.model' are located, I can run the program from the command line with 'test02.model' and obtain results. I made a copy of 'test01.model' and renamed it to 'test02.model' and still have the same problem.

What can I do so that 'test02.model' can be used as input to my .exe program using MATLAB?