How to count numbers considering all consecutives as one??

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Mohammad 2013-1-20

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Hi, I need to count some numbers like: Data=2, 3, 4, 7,8 9, 10, 20,25,27; Now, counting should be: 2,3,4=1; 7,8,9,10=1; 20=1; 25=1; 27=1; Total count=5 (1+1+1+1+1) i.e. consecutive numbers should be count as one together and any individual value should be one. Any help regarding matlab programming would be highly appreciated. Thanks in advance. Badrul

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Shashank Prasanna 2013-1-20

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编辑：Shashank Prasanna 2013-1-20

在 MATLAB Online 中打开

Data=[2, 3, 4, 7,8 9, 10, 20,25,27];
sum = 1; % The first set is counted.
for i = 2:length(Data)
      if Data(i)~=Data(i-1)+1
          %Data(i)
          sum=sum+1;
      end
end
disp(sum)

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Azzi Abdelmalek 2013-1-20

Don't use sum and i as variables. sum is the function that sums the elements of an array, and i is used to represent complex numbers

Shashank Prasanna 2013-1-20

Azzi, Its perfectly fine to use them since MATLAB gives the highest precedence to variables before function names. Avoid them if you plan to use these function in your program or just clear the variables right before you want to use the function:

http://www.mathworks.com/help/matlab/matlab_prog/function-precedence-order.html

However as you mentioned it is safer to avoid using them.

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Cedric 2013-1-20

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编辑：Cedric 2013-1-20

在 MATLAB Online 中打开

Here is a funny way to achieve this:

>> sum(diff(Data)>1)+1

EDIT: see my comment after Azzi's remark.

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Azzi Abdelmalek 2013-1-20

在 MATLAB Online 中打开

It still dont work. Look at this example.

Data=[1 2 3 4 7 8 7 6 2 1]

I suggest

sum(diff(Data)~=0 & diff(Data)~=1)+1

Cedric 2013-1-20

Well, the OP will pick the one that matches his requirements I guess; I don't test Data(i+1)==Data(i)+1 (consec. elements are consec. integers) in my solutions, but Data(i)==Data(j)+1 for |i-j|=1 (ordered neighbors are consec. integers).

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