Looks funny this exercise.
By assigning i to the rand function, it is creating matrices as i increases. So rand(2) creates a 2 x 2 matrix of random values , rand(3) creates a matrix of 3 x 3 and so on...
So rand(i) would be growing in dimension sizes, as i iterates. And not assigning a single random value to the ith element.
@Samiu is correct, I think, regarding the limits of j.
Well, after all, this exercise should give an image with random values only in the first column, and return the original image otherwise?
Check if it is what you're looking for.
- The attached file shows the original in the left, and a zoom in the right to show the random values assigned to the 1st column.
Cheers
clear all;
close all;
clc;
% tic
%-----------------read image
o = imread('pout.tif');
figure
imshow(o);
title('original image');
%%
[m, n] = size(o);
I = zeros(m, n);
%----------------random pixel insertion ------
for i = 1 : m
for j = 1 : n + 1
if j == 1
I(i,j) = rand;
else
I(i,j) = o(i,j-1);
end
end
end
figure
imshow(I, 'DisplayRange', []);
title('Image I')
