Problem with using symbolic expersion in function toeplitz

2020 9 18
1 个回答
回答已采纳
更新时间：2020 9 22
1 次查看（30 天）

0 个投票

I'm having some problems with the toeplitz function when using symbolic variables
syms a b c
toeplitz([a b c], [1 b/2 a/2])
I get the following error
Error using toeplitz (line 22)
Inputs must be numeric.
I'm using Matlab 2019b, I don't think this is a bug since when I open Matlab "toeplitz" function, it has that error call
Thanks in advance

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Francisco Williams
Francisco Williams 2020-9-18
update: I check the same function in Matlab 2019a and it worked. However I would like to find a workaround for the 2019b.

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

madhan ravi
madhan ravi 2020-9-18

0 个投票

Might be a bug. I didn’t have any problems with 2020a either. It’s better if you make a big report.

5 个评论
显示 3更早的评论 隐藏 3更早的评论

Francisco Williams
Francisco Williams 2020-9-21
I create my own toepliz function. Which is basically the same that Matlab had I only commented the isnumeric condition.
That's why I was a bit reluctant to report it as a bug since in the Matlab function this condition appears.
function t = toeplitzPaco(c,r)
%TOEPLITZ Toeplitz matrix.
% TOEPLITZ(C,R) is a non-symmetric Toeplitz matrix having C as its
% first column and R as its first row.
%
% TOEPLITZ(R) is a symmetric Toeplitz matrix for real R.
% For a complex vector R with a real first element, T = toeplitz(r)
% returns the Hermitian Toeplitz matrix formed from R. When the
% first element of R is not real, the resulting matrix is Hermitian
% off the main diagonal, i.e., T_{i,j} = conj(T_{j,i}) for i ~= j.
%
% Class support for inputs C,R:
% float: double, single
% integer: uint8, int8, uint16, int16, uint32, int32, uint64, int64
%
% See also HANKEL.
% Thanks to A.K. Booer for the original version.
% Copyright 1984-2017 The MathWorks, Inc.
%if ~(isnumeric(c) && (nargin < 2 || isnumeric(r)))
% error(message('MATLAB:toeplitz:nonNumericInputs'));
%end
if nargin < 2
c(1) = conj(c(1)); % set up for Hermitian Toeplitz
r = c;
c = conj(c);
else
if ~isempty(c) && ~isempty(r) && ~isequaln(r(1),c(1))
warning(message('MATLAB:toeplitz:DiagonalConflict'))
end
end
r = r(:); % force column structure
c = c(:);
p = length(r);
m = length(c);
x = [r(p:-1:2, 1) ; c]; % build vector of user data
ij = (0:m-1)' + (p:-1:1); % Toeplitz subscripts
t = x(ij); % actual data
if isrow(ij) && ~isempty(t) % preserve shape for a single row
t = t.';
end
madhan ravi
madhan ravi 2020-9-21
编辑：madhan ravi 2020-9-21
This is one of the reasons that you SHOULD NOT name a function as same as the inbuilt function!
Francisco Williams
Francisco Williams 2020-9-21
what? I didn't, I KNOW that. Check the name of the function toepliztPaco (that's my function). I just went inside the MAtlab toeplitz function copied and created my own function and commented the isnumeric condition.
As I MENTIONED in my last comment.
Francisco Williams
Francisco Williams 2020-9-22
Update
toeplizt function can indeed take symbolic in Matlab 2019b. The problem I had was that I installed Maple and click on "link to Matlab" option. This option uses Maple symbolic solver and affects other Matlab functions.
I uninstalled Maple and then everything worked as it should. No need to create my own toeplitz function

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Number Theory 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by