Legend inside a loop

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Tejas Appaji
Tejas Appaji 2020-9-18
评论： Tejas Appaji 2020-9-18
Hi,
I have made a for loop that plots 20 sets of values against time. Now I want to create a different legend name for all the 20 plots. In the code I calculate dampening co-efficient called zeta. I want the legend to say x(t) for zeta = (value). This is the code I have. I went through the forum and i understand that I have to use displayname. I am not sure how it works. Any help is greately appreciated.
% given
k = 2000;
m = 150;
x0 = 0;
v0 = 0.010;
c = (50:50:1000);
wn = sqrt(k/m);
t = (0:0.005:5);
xt = zeros(numel(c),numel(t));
zeta = zeros(1,numel(c));
wd = zeros(1,numel(c));
phi = zeros(1,numel(c));
A = zeros(1,numel(c));
for i = 1:numel(c)
zeta(i) = c(i)/(2*sqrt(m*k));
wd(i) = wn*(sqrt(1-zeta(i)^2));
phi(i) = atan((wd(i)*x0)/(v0+(zeta(i)*wn*x0)));
A(i) = (1/wd(i))*(sqrt((v0+zeta(i)*x0*wn)^2+(x0*wd(i))^2));
for j = 1:numel(t)
xt(i,j) = (A(i)*sin(wd(i)*t(j)+phi(i))*exp(-zeta(i)*wn*t(j)));
end
end
for k = 1:numel(c)
figure
% set(gcf, 'WindowState', 'maximized');
plot (t,xt(k,:))
title ('Assignment 2 Problem 1.61')
xlabel('Time')
ylabel('x(t)')
legend(' problem is here ')
end

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采纳的回答

Mario Malic
Mario Malic 2020-9-18
编辑：Mario Malic 2020-9-18
Something like this should work.
for k=1:1:length(c)
legendstr{1,k} = sprintf('zeta = %f', zetavalue); %legendstr changes size
legend(legendstr)
end
  3 个评论
显示 1更早的评论
Mario Malic
Mario Malic 2020-9-18
In your loop with variable k, you're plotting each curve, and if you add this, it creates a legend cell that contains names of curves as they increase with each loop.
Tejas Appaji
Tejas Appaji 2020-9-18
Thank you so much. That really helps.

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