0 个投票

%% Section 1: Initalization of Variables
%increments of x
x = -4:1:-1;
%
%The function we are given
y = x + (1 ./ (x.^2-1));
%% Section 2: Processing
plot(x,y)
axis([-15 15 0 15])
%I want to be able to see the y function appraching the verticle asymptote '-1' from the left but my function wont graph

2 个评论
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First, use more points:
x = -4:.1:-1;
Then remove the axis limil:
% axis([-15 15 0 15])
Serena Simpson
Serena Simpson 2020-9-18
Thank you so much!

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Star Strider
Star Strider 2020-9-18

0 个投票

The problem are the y-axis limits in the axis call.
Comment-out the axis call (as I do here) and you will immediately see the problem.
plot(x,y)
% axis([-15 15 0 15])
.

4 个评论
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Serena Simpson
Serena Simpson 2020-9-18
Thank you so much! It fixed my graph, but if I needed the x axis to be labeled from -15, to 15, how can I do that without breaking my code?
Star Strider
Star Strider 2020-9-19
use xlim rather than axis:
xlim([-15 15])
.
Serena Simpson
Serena Simpson 2020-9-19
It worked great! Thanks!
Star Strider
Star Strider 2020-9-19
As always, my pleasure!

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