Problem with rgb2gray function ?

I've made a GUI with GUIDE which makes a RGB image into binary image. I have the following code in one part of the program :
fileName = uigetfile('*.jpg');
imshow(fileName);
I = imread(fileName);
Iinitial = I;
Igray = rgb2gray(Iinitial);
I = imcomplement(I);
Igray = rgb2gray(I);
And it gives me that following error:
??? Error using ==> rgb2gray>parse_inputs at 82
MAP must be a m x 3 array.
Error in ==> rgb2gray at 35
X = parse_inputs(varargin{:});
Error in ==> lets_see>pushbutton1_Callback at 97
Igray = rgb2gray(Iinitial);
Error in ==> gui_mainfcn at 96
feval(varargin{:});
Error in ==> lets_see at 42
gui_mainfcn(gui_State, varargin{:});
Error in ==>
@(hObject,eventdata)lets_see('pushbutton1_Callback',hObject,eventdata,guidata(hObject))
??? Error while evaluating uicontrol Callback
I cannot find the problem and fix it. If somebody knows, please help. Thanks!

2 个评论

may be this is because you are choosing a gray scale image as input.and trying again to convert it to gray scale.
Yes, and that's what my solution below checks for. It checks how many color channels there are and only calls rgb2gray() if it's a color image.

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 采纳的回答

Check with your input image. It was gray image.

2 个评论

You were right! Thank you very much!
yes, I was having the same problem and it helped me. Thank you so much.

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更多回答(2 个)

You can only call rgb2gray() on a color image. Calling rgb2gray() on an image that is already gray scale will throw an error. Add this code to make sure the conversion is done ONLY on RGB images:
% Get the number of rows and columns,
% and, most importantly, the number of color channels.
[rows, columns, numberOfColorChannels] = size(Iinitial);
if numberOfColorChannels > 1
% It's a true color RGB image. We need to convert to gray scale.
Igray = rgb2gray(Iinitial);
else
% It's already gray scale. No need to convert.
Igray = Iinitial;
end

6 个评论

Perfect! This was really useful. Thanks a lot!
I found this code very useful, thank you!
Thanks for your code. It helped me
thank you! helps me a lot
Thanks for your short codes. It helps me for my project.
Thank you so much for your help.This code is very helping.

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