Passing Function results to another function

Question

Michael 2013-1-23

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/59681-passing-function-results-to-another-function

I recently ran into some behavior I though was unintuitive - given the code below, nargin prints out 1. Why isn't the second argument being passed to test2? Is there a standard way to get around this issue?

test2(test())
1
function [a,b] = test( )
a=5;
b=6;
end
function  test2( a,b)
nargin
end

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Answer 1

Matt J 2013-1-23

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/59681-passing-function-results-to-another-function#answer_72148

编辑：Matt J 2013-1-23

在 MATLAB Online 中打开

Multiple output arguments must be explicitly requested and assigned:

 [A,B]=test;
 test2(A,B)

or

 [AB{1:2}]=test;
 test2(AB{:}),

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Matt J 2013-1-23

在 MATLAB Online 中打开

or you could return your arguments in a vector

function ab = test( )
 ab=[5,6]
end
function  test2( ab)
 numel(ab)
end

Walter Roberson 2013-1-23

Right. This is a design feature of MATLAB, that when it sees that the result of a function is being passed to another function, all but the first output is discarded. This is fairly tricky to get around (I did see someone find a way once using deal() but I'm not convinced it would work.)

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