Error vertcat not using vertcat

Question

Bruno Gonzalo Reynoso 2020-9-23

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/598282-error-vertcat-not-using-vertcat

编辑： KSSV 2020-9-23

Hello, i´ve used the following line and get the vertcat error

Kx = [407 -169 0 0 0 0 0 0 0 0;-169 331 -162 0 0 0 0 0 0 0; -162 320 -158 0 0 0 0 0 0;0 0 -158 311 -153 0 0 0 0 0;0 0 0 -153 301 -148 0 0 0 0;0 0 0 0 -148 293 -145 0 0 0;0 0 0 0 0 -145 279 -134 0 0;0 0 0 0 0 0 -134 249 -115 0;0 0 0 0 0 0 0 -115 222 -107;0 0 0 0 0 0 0 0 -107 107]

I can´t understand where is the problem since i created the line in excel and it worked perfect for the following line

M=[12.5280326197757 0 0 0 0 0 0 0 0 0;0 12.5280326197757 0 0 0 0 0 0 0 0;0 0 12.5280326197757 0 0 0 0 0 0 0;0 0 0 12.5280326197757 0 0 0 0 0 0;0 0 0 0 12.5280326197757 0 0 0 0 0;0 0 0 0 0 12.5280326197757 0 0 0 0;0 0 0 0 0 0 12.5280326197757 0 0 0;0 0 0 0 0 0 0 12.5280326197757 0 0;0 0 0 0 0 0 0 0 12.5280326197757 0;0 0 0 0 0 0 0 0 0 10.519877675841]

How can i solved it?

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Stephen23 2020-9-23

Putting all of the data onto one line makes it difficult to debug. If you simply arrange the matrix line-by-line, it is quite obvious that the 3rd row is shorter than all of the other rows:

-169    0    0    0    0    0    0    0    0;
-169  331 -162    0    0    0    0    0    0    0;
-162  320 -158    0    0    0    0    0    0;          % <- shorter!
  0 -158  311 -153    0    0    0    0    0;
  0    0 -153  301 -148    0    0    0    0;
  0    0    0 -148  293 -145    0    0    0;
  0    0    0    0 -145  279 -134    0    0;
  0    0    0    0    0 -134  249 -115    0;
  0    0    0    0    0    0 -115  222 -107;
  0    0    0    0    0    0    0 -107  107

To avoid similar errors you should also use delimiting commas rather than spaces.

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Answer 1

KSSV 2020-9-23

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/598282-error-vertcat-not-using-vertcat#answer_498814

编辑：KSSV 2020-9-23

Your matrix is 10*10

Kx = [407 -169 0 0 0 0 0 0 0 0;
     -169 331 -162 0 0 0 0 0 0 0; 
	 -162 320 -158 0 0 0 0 0 0; % <-------here there are nine elements 
0 -158 311 -153 0 0 0 0 0;
0 0 -153 301 -148 0 0 0 0;
0 0 0 -148 293 -145 0 0 0;
0 0 0 0 -145 279 -134 0 0;
0 0 0 0 0 -134 249 -115 0;
0 0 0 0 0 0 -115 222 -107;
0 0 0 0 0 0 0 -107 107]

You have to add an extra zero in 3rd row

Kx = [407 -169 0 0 0 0 0 0 0 0;
     -169 331 -162 0 0 0 0 0 0 0; 
	 -162 320 -158 0 0 0 0 0 0 0; %  <---- zero added 
0 -158 311 -153 0 0 0 0 0;
0 0 -153 301 -148 0 0 0 0;
0 0 0 -148 293 -145 0 0 0;
0 0 0 0 -145 279 -134 0 0;
0 0 0 0 0 -134 249 -115 0;
0 0 0 0 0 0 -115 222 -107;
0 0 0 0 0 0 0 -107 107]