Reshape a multidimensional matrix

i have a multidimensional matrix (146x146x144) that i want to reshape (144x21316). the command reshape works "vertically", how i can reshape "horizontally" ( every rows next to another)

回答(2 个)

reshape(permute(matrix, [3, 2, 1]), 144, [ ])

9 个评论

if i check the results like matrix1(1,1,:) and matrix 2(:,1) they are not the same
m(:, :, 1) = [1:2;3:4];
m(:, :, 2) = [5:6;7:8];
What should be the result for the above matrix?
for examplei have a matrix
[ 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2 2 2 2
3 3 3 3 3 3 3 3 3 3]
i want to reshape in this way:
[ 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 ]
not this way
[1 2 3 1 2 3 ....]
Respond to my comment.
Do you know what a 3D matrix is ? The one you showed is not that , in fact I don’t know if it’s 1D, 2D , 3D or MD? When I pasted the example that you gave in MATLAB, it shows an error. Help us to help you.
i know what it is.. i told you that the first matrix is a multidimensional (146*146*144) and i want to reshape in a (144x21316). i showed to you that matrix to explain how i want to order the cells.
reshape(permute(matrix, [2, 1, 3]), 144, []).'
for examplei have a matrix
[ 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2 2 2 2
3 3 3 3 3 3 3 3 3 3]
That has one too many 3's in the last row. Correcting that problem:
A = [ 1 1 1 1 1 1 1 1 1;
2 2 2 2 2 2 2 2 2;
3 3 3 3 3 3 3 3 3];
P = reshape(A.', 1, [])
If your A array is actually a 3-dimensional (or generally N-dimensional for N > 2) you're going to want to use permute instead of the .' operator.
P2 = reshape(permute(A, [2 1]), 1, [])
To ask a similar question that madhan ravi did, for this specific array:
B = reshape(1:24, [2 3 4])
What exactly do you want the result of reshaping B to be? Give us the explicit command to create Breshaped:
Breshaped = [ % Fill in numbers here]
Once we know what you want Breshaped to be we can help you write the command to create it.

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iwant = reshape(144,[]) ;
Wont this work for you?

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