Applying function to signal

2013 1 27
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I have an I-dimensional input signal
x(t)=[x1(t),...xI(t)]T
and J-dimensional input-output function
g(x)=[g1(x),....gJ(x)]T
these functions are saved as a J-dimensional matrix, while applying these functions to the input signal I should get the J-dimensional output signal by,
yj(t)=gj(x(t)) where j={1,2....J}
How to implement this in matlab?

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-1-27
编辑：Azzi Abdelmalek 2013-1-27

0 个投票

function J=yourfunction(I)
%write your code
%J=...

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Berbia
Berbia 2013-1-27
I mean both x(t) and g(x) are matrices with real values..what I have to do to get y(t)? for g(x(t)), is it enough to multiply both matrices?
Azzi Abdelmalek
Azzi Abdelmalek 2013-1-27
Can you provide an example?
Berbia
Berbia 2013-1-27
编辑：Berbia 2013-1-27
size(x)=[500 5], where t=5
size(g)=[200 5]
my output signal should be size(y)=[200 5]
its possible to change the size of g as required but the size x and y should be same..
Azzi Abdelmalek
Azzi Abdelmalek 2013-1-27
编辑：Azzi Abdelmalek 2013-1-27
I dont know what you mean by as required. Can you give a clear example with relation between inputs and outputs
Berbia
Berbia 2013-1-27
I'm trying to extract the slow features from the input signal by using the algorithm Slow Feature Analysis(SFA) by using the sfa-toolkit. I'm expecting the output should be 200*5, but the tool-kit returns the output signal of dimension 500*5, where 500 is the input signal dimension.
while I changing the Slow function dimension I met with the error
??? Error using ==> mtimes
Inner matrix dimensions must agree.
so I'm wondering the dimension of g(x) which should result me the output of dimension 200*5. Anyway I can manage my project, thank you for your time and consideration.
Azzi Abdelmalek
Azzi Abdelmalek 2013-1-27
Sorry, I can't understand.

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Berbia
Berbia
2013-1-27

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