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How to arrange the values of the matrix according to index number?

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AS
AS 2020-9-28
回答： madhan ravi 2020-9-30
I have index number of matrix A =[1 3 5 6], B= [ 2 4]. The values corresponding to index number matrix A is A1=[3 4 -7 5; 2 5 10 -9; -11 56 9 -4; 6 -7 4 20] and the values corresponding to index number matrix B is B1=[13 4 -70 51; -1 95 12 -9].
I want to generate a matrix C with index number of A and B after sorting like C=[ 1 2 3 4 5 6] and the values of the matrix C1 will arrange according to the index numb of C.
How will be arranging the values of C1 from A1 and B1 according to the index number C? Please help on this
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AS
AS 2020-9-28
编辑：madhan ravi 2020-9-28
C_new is showing index number only and its va;ue will be
C_value= 4 by 6
3 13 4 -1 -7 5
2 4 5 95 10 -9
-11 -70 56 12 9 -4
6 51 -7 -9 4 20
Final output will 4 by 6 matrix.
I have tried with taking C_value=zeros(4, 6) and then try to store the values from A1 and B1 with their proper index number. But unable to do.

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采纳的回答

madhan ravi
madhan ravi 2020-9-28
编辑：madhan ravi 2020-9-28
C_new = zeros(numel(A), numel([A, B]));
C_new(:, A) = A1;
C_new(:, B) = B1.'

更多回答（1 个）

madhan ravi
madhan ravi 2020-9-30
A faster version of the other answer:
C_new = zeros(numel(A), numel([A, B]));
[IX, ix] = sort([A, B]);
C_new(:, IX) = [A1, B1.'];
C_new = C_new(:, ix)

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