How to avoid the rounding off of data ?

70 次查看（过去 30 天）
Mahesh Babu Dhanekula
评论： Steven Lord 2020-9-30
I am trying to perform the following divison operation.
l = 2.093750000000000e+09;
l/10^9
It was giving the output as:
ans =
2.0938
But i need the output as 2.09375 only. How an i achieve it ? I want to use it in further calculations as 2.09375 only. Is there any way to achieve this ?
l = 2.187500000000000e+09;
l/10^9
This was giving desired output in this case.
ans =
2.1875
If anybody knows how to solve this, please share your thoughts.

请先登录，再回答此问题。

回答（1 个）

Arthur Roué
Arthur Roué 2020-9-30
编辑：Arthur Roué 2020-9-30
There is no problem here, the default display format is set to short. Try :
format long
l = 2.093750000000000e+09;;
l/10^9
ans =
2.093750000000000
You can also access to the variable with the variable inspector : just double click on your variable in the workspace explorer.
  5 个评论
显示 3更早的评论
Mahesh Babu Dhanekula
Mahesh Babu Dhanekula 2020-9-30
Thanks for reading my 2 questions. This is exactly what i needed steven.
I have a number 2.093750000000000e+09, and I want to to covert this into 2.09375Hz. So how can i do this ?
If there is any way, please let me know steven
Steven Lord
Steven Lord 2020-9-30
Use fprintf or num2str to create a string or char vector with the desired format then concatenate it with the string "Hz" using +.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by