how can I change my code for parallel processing?
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This is my original code without parfor
For i1=1:1:nrr1
disp(i1);
if (varran(i1) < threshold)
labe(i1)=0;
mvqcoder(e)=[meanranr(i1)];
mvqcodeg(e)=[meanrang(i1)];
mvqcodeb(e)=[meanranb(i1)];
e=e+1;
mvqcode=cat(3, mvqcoder, mvqcodeg, mvqcodeb);
else
labe(i1)=1;
[domr]=domsearch(rang1r(i1,:),dompoolr,gsize,ci1r(i1),ci2r(i1),ci3r(i1),msr(i1),mdr,cd1r,cd2r,cd3r,mscr);
[domg]=domsearch(rang1g(i1,:),dompoolg,gsize,ci1g(i1),ci2g(i1),ci3g(i1),msg(i1),mdg,cd1g,cd2g,cd3g,mscg);
[domb]=domsearch(rang1b(i1,:),dompoolb,gsize,ci1b(i1),ci2b(i1),ci3b(i1),msb(i1),mdb,cd1b,cd2b,cd3b,mscb);
dom=[domr,domg,domb];
[rz cz]=size(dom);
meanrar=mean(rang1r(i1,:));
meanrag=mean(rang1g(i1,:));
meanrab=mean(rang1b(i1,:));
meanra=cat(3,meanrar ,meanrag,meanrab);
for z=1:1:cz
dompolr(z,:)=dompoolr(dom(z),:);
end
for z=1:1:cz
dompolg(z,:)=dompoolg(dom(z),:);
end
for z=1:1:cz
dompolb(z,:)=dompoolb(dom(z),:);
end
dompol=cat(3,dompolr,dompolg,dompolb);
[isomer alphr meanrr dom1r errr]=affwerrqt(rang1r(i1,:),dompolr(1:cz,:),gsize);
[isomeg alphg meanrg dom1g errg]=affwerrqt(rang1g(i1,:),dompolg(1:cz,:),gsize);
[isomeb alphb meanrb dom1b errb]=affwerrqt(rang1b(i1,:),dompolb(1:cz,:),gsize);
cdom1r(w1)=dom(dom1r);
isome1r(w1)=isomer;
alph1r(w1)=alphr;
meanr1r(w1)=meanrar;
cdom1g(w1)=dom(dom1g);
isome1g(w1)=isomeg;
alph1g(w1)=alphg;
meanr1g(w1)=meanrag;
cdom1b(w1)=dom(dom1b);
isome1b(w1)=isomeb;
alph1b(w1)=alphb;
meanr1b(w1)=meanrab;
cdom1=cat(3,cdom1r,cdom1g,cdom1b);
isome1=cat(3,isome1r,isome1g,isome1b);
alph1=cat(3,alph1r,alph1g,alph1b);
meanr1=cat(3,meanr1r,meanr1g);
vqcode3r(c,:)=[isome1r(w1),alph1r(w1),meanr1r(w1),cdom1r(w1)];
vqcode3g(c,:)=[isome1g(w1),alph1g(w1),meanr1g(w1),cdom1g(w1)];
vqcode3b(c,:)=[isome1b(w1),alph1b(w1),meanr1b(w1),cdom1b(w1)];
c=c+1;
vqcode3=cat(3,vqcode3r,vqcode3g,vqcode3b);
end
w1=w1+1;
end
Any one please give me a solution for this problem .
3 个评论
Randy Souza
2013-2-12
I have restored the original text of this question.
PRIYANGA, this question has a clear subject and an accepted answer, so it may be valuable to someone else in the future. If you have a good reason why it should be removed from MATLAB Answers, please flag the question, explain why it should be deleted, and an administrator or high-reputation contributor will consider deleting the question. Please do not simply edit your question away.
采纳的回答
Walter Roberson
2013-1-30
The part of that code that can be translated to use "parfor" would come out as,
parfor i1=1:1:nrr1
if (varran(i1) < threshold)
labe(i1)=0;
else
labe(i1)=1;
end
end
The rest of the code in your "for" loop depends upon the order of executing the iterations and so cannot be changed to use "parfor".
3 个评论
Walter Roberson
2013-1-30
You need to go through the code and figure out which variables you want to save the i1'th version of, and which variables you only need temporarily during any particular i1 iteration, and which variables you need the (i1-1)'th version of to calculate the i1'th version. If there are any variables that need the (i1-1)'th version to calculate the i1'th version, that the calculation of those variables cannot be done within parfor.
Have a look at, for example, vqcode3 : you overwrite it in every iteration of i1, and you never use it in computation, so the sequential "for" is going to end up with vqcode3 being what was calculated for vqcode3 in the last iteration of i1 (when i1 = nrr1). You cannot simply code that into "parfor" because "parfor" can execute the iterations in any order. You could use something like
if i1 == nrr1
vqcode3{i1} = ... the value
end
and not write anything in the other iterations. But if you were going to do that you might as well just compute it after the entire parfor loop based upon the variables you did save.
If you are not calculating vqcode3 for any but the last iteration, then there are other variables that do not need to be calculated, and then since those are not needed, other variables do not need to be calculated either. You might find that a fair bit of what you are calculating now is not needed inside the loop.
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