Pdepe: Spatial discretization has failed. Discretization supports only parabolic and elliptic equations, with flux term involving spatial derivative.

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Luigi Piero Di Bonito
编辑： Luigi Piero Di Bonito 2020-10-3
Hi,
I was trying to solve PDEs system about diffusion on catalyst (modeled by deactivation model), which yields:
Error using pdepe (line 293)
Spatial discretization has failed. Discretization supports only parabolic
and elliptic equations, with flux term involving spatial derivative.
Error in Resolution (line 30)
sol = pdepe(m,@eqn2,@initial2,@bc2,x,t);
After read model in attchament, please see the code below:
global Def T Dp R cAO k kd kO cW alphaO gamma
%Parameters
T = 333; %[=]K
Dp = 2; %[=]m
Def = 10^-5; %
cAO = 0.0001; %[=]kmol/m^3 intial valure of concentration
cW = 0.0001;%[=]kmol/m^3
R = Dp/2;
k = (1.191*10^5)*exp(-7.544/(0.001607460438947*T));
kd = (4.299*10^3)*(exp(-6.86/(0.002102114315754*T)));
kO =k*cW;
gamma = 1;
alphaO = 1; %intial value of catalyst activity
%PDE2: MATLAB script M-file that solves the PDE
%stored in eqn2.m, bc2.m, and initial2.m
m = 2; %spheric
x = linspace(0,R,10);
t = linspace(0,1,10);
sol = pdepe(m,@eqn2,@initial2,@bc2,x,t);
u1 = sol(:,:,1);
u2 = sol(:,:,2);
%--------------------------------------------------------
%EQN2: MATLAB M-file that contains the coefficents for
%a system of two PDE in time and one space dimension.
function [c,b,s] = eqn2(x,t,u,DuDx)
global Def kO kd gamma
c = [1; 1];
b = [Def; 0] .* DuDx;
s = [- kO*u(1)*(u(2));-kd*u(1)*((u(2)).^(gamma+1))];
% --------------------------------------------------------
%INITIAL2: MATLAB function M-file that defines initial conditions
%for a system of two PDE in time and one space variable.
function value = initial2(x);
global cAO alphaO
value = [cAO; alphaO];
% --------------------------------------------------------
%BC2: MATLAB function M-file that defines boundary conditions
%for a system of two PDE in time and one space dimension.
function [pl,ql,pr,qr] = bc2(xl,ul,xr,ur,t)
global cAO R
pl = [0; 0];
ql = [1; 0];
pr = [ur(R)-cAO; 0];
qr = [0; 0];

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采纳的回答

Bill Greene
Bill Greene 2020-10-3
编辑：Bill Greene 2020-10-3
The boundary conditions for your second PDE are invalid. These should work:
pl = [0; 0];
ql = [1; 1];
pr = [ur(1)-cAO; 0];
qr = [0; 1];
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