minutes to hour and minutes

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Waqas Siddique
Waqas Siddique 2020-10-5
I have a function that converts minutes to hours and minutes. it takes the value of minutes(mins) only once. However I want to update the value of variable mins several times(eg 10) so the variable output(test) is also updated the same number of times. How can I do this with example values of variable mins (60, 120,180,240,300).
hr_min = @(mins) [fix(mins/60) rem(mins,60)]; % Minutes —> [Hrs Min]
mins = 180; % Test Data
test = hr_min(mins) % Test Output

回答(2 个)

James Tursa
James Tursa 2020-10-5
Make mins a column vector, or use mins(:) in your function handle.

Star Strider
Star Strider 2020-10-5
Use the (:) subscript convention to forec the ‘mins’ argument to be a column vector:
hr_min = @(mins) [fix(mins(:)/60) rem(mins(:),60)]; % Minutes —> [Hrs Min]
then:
test = hr_min([60, 120,180,240,30])
produces:
test =
1 0
2 0
3 0
4 0
0 30
.

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