pop=randi([100],20,8);
[r1,c1]=size(pop);
for i=1:r1
A=randi(100);
if A<=90
pool(i,:)=pop(i,:);
end
end
Hi
I want if the condition is not met, the pool variable does not take any value, in other words, in the end, for example, it becomes an 18x8 matrix, not an 20x8 matrix with 2 rows containing the value 0
Thank you for your guidance

 采纳的回答

KSSV
KSSV 2020-10-5
编辑:KSSV 2020-10-5
pop=randi([100],20,8);
[r1,c1]=size(pop);
pool = zeros([],c1) ;
count = 0 ;
for i=1:r1
A=randi(100);
if A<=90
count = count+1 ;
pool(count,:)=pop(i,:);
end
end
You need not to use loop...it can be vectorized.
pop=randi([100],20,8);
[r1,c1]=size(pop);
A = randi(100,1,r1) ;
pool = pop(A<=90,:) ;

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