Different results using mesh and surf

Question

Nathan Shapiro 2020-10-5

0
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https://ww2.mathworks.cn/matlabcentral/answers/605341-different-results-using-mesh-and-surf

评论： Adam Danz 2020-10-5

I'm trying to graph the function xye^(-(x.^2+y.^2)), and I used both surf and mesh to do so. Below is the code. The problem is the two graphs are different. The surf function seems to have gotten it correct, but the mesh function looks like it graphed the absolute value of the function. Why is there this difference?

clear
clc
r=100;
x1 = linspace(-10,10,r);
y2 = linspace(-10,10,r);
[x,y] = meshgrid(x1,y2);
z=x.*y.*exp(-(x.^2+y.^2));
figure
surf(x,y,z)
xlabel('x');
ylabel('y');
zlabel('z');
grid on
shading interp
colorbar
figure
mesh(x,y,z.^2)
xlabel('x');
ylabel('y');
zlabel('z');
grid on

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Answer 1

Adam Danz 2020-10-5

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https://ww2.mathworks.cn/matlabcentral/answers/605341-different-results-using-mesh-and-surf#answer_505438

编辑：Adam Danz 2020-10-5

在 MATLAB Online 中打开

> The problem is the two graphs are different. The surf function seems to have gotten it correct, but the mesh function looks like it graphed the absolute value of the function

Hint

mesh(x,y,z.^2)
%         ^^^

Also see the difference in the z-axis values. The range of z values in the mesh version is not the absolute value of the z values in the surf version, it's squared (which forces negative values to be positive).