1x10 matrix using a single while loop
显示 更早的评论
n = 10;
A =zeros(1,n);
count=1;
while i==1 && j==1:n;
count=count+1;
A(i,j)=count;
end
display(A)
trying to get this to display A=[1 2 3 4 5 6 7 8 9 10] using exactly 1 while loop.
1 个评论
Walter Roberson
2020-10-5
while i==1 && j==1:n;
j==1:n is a vector comparison, with a vector result (length 10). You cannot use a vector together with the && operator.
Also, your while loop does not change i or j, so your loop would be infinite if it was accepted at all.
采纳的回答
Pink_panther
2020-10-5
n=10;A =zeros(1,n);k=1;
while k <=n
A(k)=k
k=k+1;
end
更多回答（2 个）
Walter Roberson
2020-10-5
variable = initial_value;
while variable <= final_value
do something with variable
variable = variable + increment;
end
Pink_panther
2020-10-5
OP was asking for one liner.
Here is the shorter verion, it worked on my PC.
n=10;A=[];k=1;while k <=n,A=cat(2,A,k),k=k+1;end
2 个评论
Rik
2020-10-5
You didn't format this as code, and it actually performs worse than your other answer, because it dynamically grows the array. Other than that it is identical to your other answer. What would be the benefit? Compressing code into a one-liner doesn't usually improve code readibility and doesn't change performance.
Walter Roberson
2020-10-5
The poster asked for exactly one while loop, but did not ask for a one-liner.
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