definition of ellipticF in mfun, error updating code using mfun('EllipticF'...) to ellipticF

4 次查看（过去 30 天）

显示更早的评论

Anthony Sigillito 2020-10-7

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/607401-definition-of-ellipticf-in-mfun-error-updating-code-using-mfun-ellipticf-to-ellipticf

评论： Uday Pradhan 2020-10-14

在 MATLAB Online 中打开

I'm trying to run some code I wrote back in 2012 that used to use the expression:

phi(jy,jx) = real(mfun('EllipticF',z/a,k));

but when I run it now there is a warning message that says:

Warning: Functions 'mfun' and 'mfunlist' will be removed in a future release. Instead, use the
appropriate special function. For example, use 'bernoulli(n)' instead of mfun('bernoulli',n).

This is fine, I tried rewriting the code using

phi(jy,jx) = real(ellipticF(z/a,k^2));

where the k^2 is due to the change in definition between the old and new functions. This gives results that are qualitatively very different than what I get using the mfun function so I assume I made some error in changing the definition between the two functions. However, I can't documentation showing the definition of mfun('EllipticF'...) so its hard to compare. I'm not sure where I'm going wrong so it would be good if someone could share what the definition of the mfun('EllipticF'...) integral is. Or if you see where I've made my mistake, I'd appreciate it. I assume that maybe both arguments of the function have changed, but just can't find the documentation.