check if an array is equispaced

2020 10 12
2 个回答
回答已采纳
更新时间：2020 10 12
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I am given a vector of numbers and I have to check if this vector has its samples equispaced or not. How can I do it without using fors?

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Ameer Hamza
Ameer Hamza 2020-10-12
编辑：Ameer Hamza 2020-10-12

1 个投票

Something like this
x = [1 2 3];
dx = diff(x);
is_equidistant = all(dx==dx(1));
Result
>> is_equidistant
is_equidistant =
logical
1
If
x = [1 2 5];
dx = diff(x);
is_equidistant = all(dx==dx(1));
Result
>> is_equidistant
is_equidistant =
logical
0
If you want to check it with a tolerance value
x = [1 2 3.00000000000001];
dx = diff(x);
is_equidistant = all(ismembertol(dx, dx(1)));
Result
>> is_equidistant
is_equidistant =
logical
1

更多回答（1 个）

Stephen23
Stephen23 2020-10-12
编辑：Stephen23 2020-10-12

1 个投票

>> v = [1,2,3,4,5,6,7];
>> x = ~any(diff(v,2))
x = 1
>> v = [1,2,4,4.5,7];
>> x = ~any(diff(v,2))
x = 0

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