EDIT — (13 Oct 2020 at 12:53)
(Question was essentially completely changed.)
To clarify, it is not a double array, because the leading zeros would not be present. Most likely is’s a cell array:
v = {'0100001' '0100100'};
and it’s relatively straightforward (although not at all obvious) to get the result you want:
Out = reshape([v{:}]-'0', [],1)
producing:
Out =
0
1
0
0
0
0
1
0
1
0
0
1
0
0
.
