one script two anonymous functions

2020 10 13
2 个回答
更新时间：2022 11 6
4 次查看（30 天）

0 个投票

I do not undestand when I wrong in my code
thank you so much for yor help
ThirdSide = @(a,b,C) sqrt(a^2+b^2-(2*a*b*cos(C)));
TriangleArea = @(a,b,C) ((a*b)/2)*sin(C);
SideC =ThirdSide(5,8,50*pi/180)
AreaABC=TriangleArea(5,8,50*pi/180)

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回答（2 个）

Steven Lord
Steven Lord 2020-10-13

1 个投票

Based on the problem description I'm guessing C is an angle in degrees, not radians. If that's the case take a look at the sind function.
Fanele
Fanele 2022-11-6
移动：Image Analyst 2022-11-6
Ran in:

0 个投票

Ran in:
ThirdSide=@(a,b,C) sqrt(a^2+b^2-2*a*b*cos(C*pi/180))
ThirdSide = function_handle with value:
@(a,b,C)sqrt(a^2+b^2-2*a*b*cos(C*pi/180))
TriangleArea=@(a,b,C) (((a*b)/2)*sin(C*pi/180))
TriangleArea = function_handle with value:
@(a,b,C)(((a*b)/2)*sin(C*pi/180))
SideC=ThirdSide(5,8,50)
SideC = 6.1300
AreaABC=TriangleArea(5,8,50)
AreaABC = 15.3209

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