sum of series of following equation

2 次查看(过去 30 天)
lamda=0.3:0.01:1.4; % unit micro-meter
Ec2=(1.24./lamda);
alpho=2e4;
alpha= real(alpho.*(sqrt(Ec2-1.51)));
d=1e-4;
JPh2=exp(-1.*alpha.*d); % equation 1
lamda1=0.82;
% now the summation of eqaution 1 goes from 0 to lamda1,
so how to calculate this sum of series

采纳的回答

Ameer Hamza
Ameer Hamza 2020-10-14
You can use logical indexing to isolate the required values and then use sum()
lamda=0.3:0.01:1.4; % unit micro-meter
Ec2=(1.24./lamda);
alpho=2e4;
alpha= real(alpho.*(sqrt(Ec2-1.51)));
d=1e-4;
JPh2=exp(-1.*alpha.*d); % equation 1
lamda1=0.82;
idx = lamda < lamda1;
out_value = sum(JPh2(idx));

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by