Sorting and replacing data in matlab
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Hi all,
I have a position Array suppose "A"
A =[ 1, 0, 3, 4, 5, 6, 7, 8, 0, 0,15, 20, 10, 9].
I want to replace all those values of A which are grater than 5.
Here, the first element (in A, it is 6) which is grater than 5 will be replaced by a constant say c1
Then next element (in A, it is 7) which is grater than 5 will be replaced by a constant say c2 =c1+ a, where 'a' is a constant
After that the next element (in A, it is 8) which is grater than 5 will be replaced by a constant say c3 =c2+ a, where 'a' is a constant
...... So on.
I want to see the final Array like this
A =[ 1, 0, 3, 4, 5, c1, c2, c3, 0, 0, c4, c5, c6, c7].
N.B. if any element of A is less or equal than 5, the elements of A will be unchanged
采纳的回答
Ameer Hamza
2020-10-15
编辑：Ameer Hamza
2020-10-15
Here is a vectorized alternative:
A = [ 1, 0, 3, 4, 5, 6, 7, 8, 0, 0,15, 20, 10, 9];
a = 1; c1 = 10;
idx = A > 5;
A(idx) = c1 + (0:nnz(idx)-1)*a;
Result
>> A
A =
1 0 3 4 5 10 11 12 0 0 13 14 15 16
更多回答（1 个）
Alan Stevens
2020-10-15
Here's one way:
A =[ 1, 0, 3, 4, 5, 6, 7, 8, 0, 0,15, 20, 10, 9];
c1 = 0.1; a = 0.01;
ix = find(A>5);
for i = 1:numel(ix)
A(ix(i)) = c1+(i-1)*a;
end
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