Loading in a for loop

Question

0 个投票

im in a situation on which i have to load a lot of files (about 400) and was wondering if there were a smart way to do it.

I was thinking that a for loop was the best way to do it, but the for loop does not recognise the 'i' as the variable.

for i=1:400
    run_i='C:\Users\unknown\run_i'
end

is there a simple way to solve this?

2 个评论
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Stephen23 2020-10-15

"is there a simple way to solve this? "

Tim Johansson 2020-10-16

Thanks, it worked.

Answer 1

Sudhakar Shinde 2020-10-15

编辑：Sudhakar Shinde 2020-10-15

0 个投票

You can use 'int2str'

for i=1:400
    run_i=['C:\Users\unknown\run_',int2str(i)];
end
%or
for i=1:400
    run_i=strcat('C:\Users\unknown\run_',num2str(i));
end

Stephen23 2020-10-15

Or use the recommended and more versatile sprintf.

Tim Johansson 2020-10-16

Thanks for the help