for-loop to create vector

2020 10 15
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更新时间：2020 10 16
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I am just learning for end loops.
I am trying to create a for end loops that can find the maximum value of each column of a matrix and store the results in a single vector.
I have ankle moment data and I want to identify the maximum moment of each stride (column in the data) using a for-loop to store the results in a vector.

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Ameer Hamza
Ameer Hamza 2020-10-15
编辑：Ameer Hamza 2020-10-15

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Since you insist on using for-loop
M; % your matrix
n = size(M, 2); % number of columns
max_vals = zeros(1, n);
for i = 1:n
max_vals(i) = max(M(:,i));
end
Without for-loops
max_vals = max(M);

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Slane Haltine
Slane Haltine 2020-10-15
编辑：Slane Haltine 2020-10-15
The code seems to work but I recieve an output of max_vals which is only one number, which is the maximum value. As opposed to a vector containing the max values of each column.
n = size(Force,10);
max_vals = zeros(1,n);
for i = 1:n
max_vals(i) = max(Force(:,i));
end
Rik
Rik 2020-10-15
Have you read the documentation for the size function? You're asking for the tenth dimensions. I doubt you have that many.
Slane Haltine
Slane Haltine 2020-10-15
编辑：Slane Haltine 2020-10-15
Okay, I was confused by the original code stating %number of columns
Thank you, I have read it but was misinterpretting it before.
In that case it absolutely works but how can I have the output as a column vector instead of a a row?
Ameer Hamza
Ameer Hamza 2020-10-15
If you want output to be in column vector form then initialize like this
max_vals = zeros(n,1);
Slane Haltine
Slane Haltine 2020-10-15
Thank you very much!
Ameer Hamza
Ameer Hamza 2020-10-15
I am glad to be of help!
Slane Haltine
Slane Haltine 2020-10-15
I am a bit confused about the use of zeros in this line of code. The code works perfectly, but can you elaborate as to what this line is calling for?
Ameer Hamza
Ameer Hamza 2020-10-15
Read about pre-allocation in MATLAB. It is just there to make the code more efficient. Removing it will not cause any error but the code can get very slow if the array needs to be large.
Rik
Rik 2020-10-15
Have you read the documentation? It is one of the major benefits of Matlab over competing software.
Slane Haltine
Slane Haltine 2020-10-15
编辑：Slane Haltine 2020-10-15
I think I understand and I see how it can make the code much more efficient for a much larger array. If i remove it, the values are given in a row vector again.
This is what confuses me as to its function in this code.
for example, without it, this is how I would write the code.
n = size(Force,2);
max_vals = 0;
for i = 1:n
max_vals(i) = max(Force(:,i));
end
max_column = reshape(max_vals,10,1)
Rik
Rik 2020-10-15
You can make it a row vector if you prefer. It is good to form the habit when you learn, so you don't need to unlearn bad habits later.
Slane Haltine
Slane Haltine 2020-10-15
I mean to say, I added the reshape line at the end of the code because removing the zeros line results in a row instead of a column. That confuses me as to what the zeros command is doing in that line of code and how it makes the difference between the max_vals resulting in a row or column vector.
Rik
Rik 2020-10-15
If you don't specify two coordinates, Matlab will attempt to figure out which dimensions should be extended to make your data fit. The default is to grow in the first dimension. If you create the array with a specific shape, Matlab will extend that. So you can choose between zeros(1,n); or zeros(n,1); (or more exotic shapes like zeros(1,1,n);).
Slane Haltine
Slane Haltine 2020-10-15
Awesome, thank you!
Ameer Hamza
Ameer Hamza 2020-10-16
Note that If you just want to conver a row vector to a column vector then you can even use
max_column = max_column(:);
% or
max_column = max_column.'; % in this case, max_column must be a row vector

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