Filling out multiple structures in an if loop

Question

Tim Johansson 2020-10-16

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/616053-filling-out-multiple-structures-in-an-if-loop

评论： Ameer Hamza 2020-10-19

采纳的回答： Ameer Hamza

在 MATLAB Online 中打开

Im trying to set up some data to use in machine learning, but i am having a hard time setting up the data.

Right now im trying to sort my data into different structures according to label.

for k = 1:20
 if  rawData.sub1.run.label{1, 1}.data(k,3) == 0
     classData.sub1.right{k}=rawData.sub1.run.epochs.run1.movement{k}
    elseif rawData.sub1.run.label{1, 1}.data(k,3) == 1
     classData.sub1.up{k}=rawData.sub1.run.epochs.run1.movement{k}
    elseif rawData.sub1.run.label{1, 1}.data(k,3) == 2
     classData.sub1.left{k}=rawData.sub1.run.epochs.run1.movement{k}
    elseif rawData.sub1.run.label{1, 1}.data(k,3) == 3
     classData.sub1.down{k}=rawData.sub1.run.epochs.run1.movement{k} 
 end
end

My problem is the "right{k}" ... down{k} structures.

if i dont input a k, the loop will simply replace the data that is already placed in the structure with the new data that belongs in the scructure.

However if i give the input k, multiple cells inside the structure is left as null, making it hard to call for the data again.

I've been reading up on structures but cant seem to find a simple solution.

i was thinking if it was possible to have a integer that only changed value every forth loop?

Any ideas are appreciated

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Answer 1

Ameer Hamza 2020-10-16

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/616053-filling-out-multiple-structures-in-an-if-loop#answer_516073

在 MATLAB Online 中打开

If you want an integer which only increment every fourth iteration then you can use ceil() or floor() functions. For example

for k = 1:20
    disp(ceil(k/4))
end

Result

>> for k = 1:20
    disp(ceil(k/4))
end
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