why this error ??

1 次查看（过去 30 天）
Kenza Boukallouch
Kenza Boukallouch 2020-10-16
回答： Image Analyst 2020-10-16
x=[-90 -90 -90 -90 -90 -45 -45 -45 -45 -45 0 0 0 0 0 45 45 45 45 45 90 90 90 90 90,45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45];
n=1;
when n<26;
f=0;
p=1/2*acosd(sqrt((1-sind(2*x(2,n))*sind(2*x(2,n)))/(1+tan(2*x(1,n))*tand(2*x(1,n)))));
ax=sqrt(1/(tand(p)*tand(p)+1));
ay= sqrt(1-ax^2);
d=acosd(tan(2*x(1,n))*sqrt((1-(sind(2*x(2,n))*sind(2*x(2,n))))/(tan(2*x(1,n))+((sind(2*x(2,n)))*(sind(2*x(2,n)))))));
f1=['simulation ',num2str(n)];
disp(f1);
f2=['ax=',num2str(ax),' ','ay=',num2str(ax),' ','d=',num2str(ax),' ','p=',num2str(p)];
disp(f2);
n = n+1;
end
Index in position 1 exceeds array bounds (must not exceed 1).

请先登录，再回答此问题。

回答（2 个）

Alan Stevens
Alan Stevens 2020-10-16
You have defined x as a 1x25 vector, but you are calling it with two arguments. You need to call it with x(n), rather than x(1,n) and x(2,n).
You probably also should use "while" rather than"when".
Image Analyst
Image Analyst 2020-10-16
x has only one row, not two. So what value are you thinking of when you try to get the value in row 2, column n? Why do you think there should even be a x(2, n)???
Plus you must use while instead of when, or else just use a for loop
for n = 1 : 25

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by