How to code my own Reshape function without using the built in reshape()??

11 次查看(过去 30 天)
Im essentially trying to make a function ---> function [matrix] = myReshape(vector, m, n) that takes in a 1d vector and dimensions m and n, and makes it a 2d matrix as shown above with the m and n provided.
How can I go about this?
  2 个评论
James Tursa
James Tursa 2020-10-16
编辑:James Tursa 2020-10-16
Since MATLAB stores values in column order, note that your proposed "reshape" reorders the values in memory. I.e., it does not do the same thing as the MATLAB reshape( ) function. You have the equivalent of a transpose mixed in with this operation.
Coleman tyson
Coleman tyson 2020-10-16
I see. Though transpose wouldn't necessarily work for me because if I want to end up with an uneven matrix of dimensions 3x4, I couldn't reshape and then transpose the reshaped matrix, because it would result in a 4x3 matrix ://

请先登录,再进行评论。

采纳的回答

Matt J
Matt J 2020-10-16
编辑:Matt J 2020-10-16
Hint: Notice the effect of doing things like this:
A=nan(3,4);
A(:)=1:12
A = 3×4
1 4 7 10 2 5 8 11 3 6 9 12
  7 个评论
Matt J
Matt J 2020-10-16
编辑:Matt J 2020-10-16
I recommend that you work backwards from the solution. What if you took the result that you are trying to get, and transposed that? What would that look like?

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by