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how to find a root of polynomial using matlab

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mustafa jbara
mustafa jbara 2020-10-18
编辑： Alan Stevens 2020-10-18
C (y) = 1 + 3 tan( y/√2)

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回答（2 个）

KSSV
KSSV 2020-10-18
sym c(y)
c(y)= 1+3*tan(y/sqrt(2))==0 ;
r = solve(c,y) ;
double(r)
Alan Stevens
Alan Stevens 2020-10-18
Or directly
y = sqrt(2)*atan(-1/3);
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Alan Stevens
Alan Stevens 2020-10-18
编辑：Alan Stevens 2020-10-18
That gives you a root! i.e. a value of y that makes the expression 1+3*tan(y/sqrt(2)) equal zero.

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