Regular matrix and non-singular matrix
显示 更早的评论
Hey
I need to write a function that the user enters a matrix, and the function returns "1" if the matrix is reversible(regular) and "0" if it's not.
I wrote this function-
function x=irr_mat(A)
if isequal(A,zeros(n))
x=0;
else
if size(A,1)==size(A,2)
x=1;
else
x=0;
end
end
end
n is the array of the matrix.
and I got this note-
Error in irr_mat (line 3)
if isequal(A,zeros(n))
Error in Untitled5 (line 3)
irr_mat(A)
any help?
14 个评论
Stephen23
2020-10-20
Where do you define n ?
Noa Yelin
2020-10-20
Noa Yelin
2020-10-20
Steven Lord
2020-10-20
You compute it from the input the user gave you using size.
Noa Yelin
2020-10-20
Noa Yelin
2020-10-20
Steven Lord
2020-10-20
size requires at least one input, the array whose size you're trying to compute. In this case you probably want to call it with two inputs. To see what that second input represents, I recommend reading or at least skimming the documentation page.
doc size
Noa Yelin
2020-10-20
Francesco Tricarico
2020-10-20
You've said
"I need to write a function that the user enters a matrix, and the function returns "1" if the matrix is reversible(regular) and "0" if it's not."
It seems that you're last function version works well ("1" is the expected output).
Noa Yelin
2020-10-20
Rik
2020-10-20
A is 4x4, x is not.
KSSV
2020-10-20
You asked the same question three times. There is no clarity in your question.
Noa Yelin
2020-10-20
Steven Lord
2020-10-20
What specifically do you mean by "reversible(regular)"? Which of the following count as reversible / regular and why do they count or not count?
A1 = 1
A2 = 42
A3 = 99
A4 = 12321
A5 = [1 2; 3 4]
A6 = [1 23; 23 1]
A7 = [98 89; 764 467]
A8 = [1 2 3 4; 5 6 7 8; 9 10 10 9; 8 7 6 5; 4 3 2 1]
回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Linear Algebra 的更多信息
产品
2020-10-20
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
