- a matrix padded with NaN (or some other value).
- a container array (e.g. cell array) of vectors.
How to make a loop through each row?
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Hi! I have a variable A in the size of 50x15000 with different numbers. And I have variable B, the same size 50x15000, that has only zeros and ones. I want to filter the data in the variable A based on variable B, and put the result in variable C. I need to take the numbers from A only if it is zero in the matrix B. One row is one trial in both A and B.
I wrote a small for loop:
C = NaN(size(A));
for i = 1:size(A,1)
C(i,:) = A(i, B(i,:) == 0);
end
The problem is that, after filtering the data, each row has different number of columns, so it doesn't want to be in one matrix. I have a message like this: "Unable to perform assignment because the size of the left side is 1-by-15000 and the size of the right side is 1-by-13683".
How can I solve this problem?
Thank you!
2 个评论
Stephen23
2020-10-21
"How can I solve this problem?"
Which would you prefer?:
回答(1 个)
David Hill
2020-10-21
编辑:David Hill
2020-10-21
Make C a cell array
for i = 1:size(A,1)
C{i} = A(i, B(i,:) == 0);
end
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