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Why can't Matlab calculate a(0)

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Michael Bernard
Michael Bernard 2013-2-4
Hi everyone, its not serious problem at all. But I just want to know. Why cant Matlab calculate a(0) in a for loop.
Example: n=3;L=4;
>> ai=[2 4 6 8];
for m=0:n
an(m)=-ai(L-m)/ai(1)
end
Matlab will give an error message that says
"Attempted to access (0); index must be a positive integer or
logical."
My question is why?? I get results if I use
for m=1:n
an(m)=-ai(L-m)/ai(1)
end
because a(1) , a(2) etc can be found in matlab. so why not a(0)???

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-2-4
编辑：Azzi Abdelmalek 2013-2-4
It's just how Matlab works, allows only positive integer or logical index. You can resolve the problem, for example
for k=0:10
y(k+1)=sin(k)
end

更多回答（1 个）

Walter Roberson
Walter Roberson 2013-2-4
You need to distinguish between array notation and function notation.
Array notation requires that the arguments describe integer array locations. Array locations in MATLAB are numbered starting from 1, as is the case for Fortran and a number of other computer languages (but not all -- e.g., C numbers starting from 0.)
function notation is what is used when you say things like
f(1.37) = 8.2
or
an(0) = 4
That notation is completely valid in mathematics, but it has no equivalent in MATLAB, except inside MuPAD (the symbolic toolbox).

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