how to return a function handle to a nested function that computed the value of a polynomialin matlab

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JAYANTHI SANKARALINGAM
评论： Purvaja 2025-3-27
how to return a function handle to a nested function that computed the value of a polynomialin matlab

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Purvaja
Purvaja 2025-3-6
编辑：Purvaja 2025-3-6
Hi @JAYANTHI SANKARALINGAMi,
To create a MATLAB function that returns a handle to a nested function, you can refer to following steps.
  1. Function Declaration: Declare a function that accepts a vector containing the polynomial coefficients (in descending order of power).
  2. Nested Function: Inside the function, declare a nested function to compute the polynomial’s value at any given x.
  3. Returning the Handle: The outer function returns a handle to nested function using the '@' operator. This allows you to evaluate the polynomial later, even though nested function is defined within outside function.
% Declare outer function
function fh = getManualPolynomialHandle(coeffs)
% Declare nested function
function y = evaluatePolynomial(x)
% Evaluate polynomial at x using coeffs
end
% Return a function handle to the nested function.
fh = @evaluatePolynomial;
end
p1 = getManualPolynomialHandle([2, -3, 5]);
result1 = p1(4);
disp(result1);
For more clarification on the functions used, you can refer to the following resources,
  1. Function Handles: https://www.mathworks.com/help/matlab/function-handles.html
  2. Nested Functions: https://www.mathworks.com/help/matlab/matlab_prog/nested-functions.html
Or you can access release specific documentation using these commands in your MATLAB command window respectively:
web(fullfile(docroot, 'matlab/function-handles.html'))
web(fullfile(docroot, 'matlab/matlab_prog/nested-functions.html'))
Hope this helps you!
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Purvaja
Purvaja 2025-3-27
Well, that was not my intention in answering. I am a beginner and in the process of learning. I started to build my competence and leveraged this forum. I started with solving some basic concepts and since no one attempted to answer this, I took up on this to help beginners like me.
I am looking forward to take up more challenging questions ahead! 😃

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