How to replace every non-0 number with the number in that place added to another number - no loops

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katherine keogh
katherine keogh 2020-10-22
编辑： Stephen23 2020-10-22
Say I have a matrix I want to loop in a cell in the matrix and change that particular cell to itself added to another number. I have tried to explain mself better with inputs and expected output in the code.
A=[1 0 3;4 5 0;8 0 9] % matrix
B=-7 %additional number
% idk what code i need but every non-zero number in that matrix must be added to b
C=[-6 0 -4; -3 -2 0; 1 0 2] % what I expect the output to be

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采纳的回答

Stephen23
Stephen23 2020-10-22
编辑：Stephen23 2020-10-22
I think it is neater to only define the index once:
>> X = A~=0;
>> A(X) = A(X)+B
A =
-6 0 -4
-3 -2 0
1 0 2

更多回答（1 个）

Andy
Andy 2020-10-22
A(A~=0) = A(A~=0) + B

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