How to save struct data in for loop

Hi,
I am working in a for loop where for each iteration I get a new structure data with 3 fields in all of them. How do I store all of these data points so that I could use them together? I tried working with the following format but I am getting the error "Subscripted assignment between dissimilar structures."
The m.get_data() returns a struct of three fields each containg 1024 values.
for i=1:10
data_struct(i)=m.get_data();
end

5 个评论

You have a left-over value for data_struct in your workspace. Clear it, or better yet use a different variable name.
Walter Roberson could you please explain what is the meaning of the error "Subscripted assignment between dissimilar structures" .And how to avoid it.
Also note that in order to assign an entire struct into an existing struct array, the structure fields must be in exactly the same order between the two.
Can i save them in any other way. My objective is to save the individual struct for eact loop.
Use dynamic structure names so your data_struct is a struct with multiple field names. Then use save() with the -struct option; that will create one variable name in the .mat file for each field name in the struct.

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 采纳的回答

You can overcome the problem by pre-allocating the array of structures as follows:
clear all; % Clear the workspace
N = 10;
% Pre-allocate the array of structures
structArray1(N) = struct('field1',[], 'field2',[], 'field3',[]);
for i=1:N
field1 = "field1";
field2 = "field2";
field3 = "field3";
structArray1(i)=getStruct(field1, field2,field3);
end
Alternatively, instead of pre-allocating before the loop, you can also loop backwards so that all the memory allocation is done in the first iteration itself.
N = 10;
for i=N:-1:1
field1 = "field1";
field2 = "field2";
field3 = "field3";
structArray2(i)=getStruct(field1, field2,field3);
end
structArray2 = fliplr(structArray2); % Get back the array of structures in correct order
The getStruct function is as follows:
function outStruct = getStruct(field1, field2,field3)
% returns a struct with 3 fields
outStruct.field1 = field1;
outStruct.field2 = field2;
outStruct.field3 = field3;
end

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