function with 4x4 combinations

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MadjeKoe
MadjeKoe 2020-10-26
评论： Rik 2020-10-26
Hi guys, i'm a beginner with matlab and i'm trying to put the below into a function. I need all combinations to be calculated. So when the err = 1, all other orientations must be subtracted from ori1. And when err = 2, all other orientations must be subtracted from ori2. Can somebody please help me with this?? I've tried a lot of different things but I cannot get it to work..
ori1 = res(:,3);
ori2 = res(:,4);
ori3 = res(:,5);
ori4 = res(:,6);
err1 = out(:,1);
err2 = out(:,2);
err3 = out(:,3);
err4 = out(:,4);
relativeorientation = ori1 - ori2
responseerror = err1
sortrows(relativeorientation,responseerror)
out = sortrows([relativeorientation responseerror]);
plot(out)
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MadjeKoe
MadjeKoe 2020-10-26
Yeah, my teacher wants me to put everything into a function. I personally also think that copy-pasted code works fine..
Rik
Rik 2020-10-26
No, I mean you can show us what you want by copy-pasting repeated code. That way we can clearly see what should happen. That way you don't need to write a complicated block of text. We will also be able to verify that the output is the exact same.
%example of copy-paste code:
rng(0);x=rand(1,5);y=rand(1,5); %set rng so the result of the three methods can be compared
x1=x(1);y1=y(1);z1=x1+y1;
x2=x(2);y2=y(2);z2=x2+y2;
x3=x(3);y3=y(3);z3=x3+y3;
x4=x(4);y4=y(4);z4=x4+y4;
x5=x(5);y5=y(5);z5=x5+y5;
z=[z1 z2 z3 z4 z5];
z_method_1=z;
Here we can clearly see what you want, so we can suggest how to implement something better:
rng(0);x=rand(1,5);y=rand(1,5);
z=zeros(size(x));
for n=1:numel(x)
z(n)=x(n)+y(n);
end
z_method_2=z;
Or better:
rng(0);x=rand(1,5);y=rand(1,5);
z=x+y;
z_method_3=z;
By setting the random seed every time, we can be sure that the input (and therefore the output) is the same every time.
clc % both statements below should return true
isequal(z_method_1,z_method_2)
isequal(z_method_1,z_method_3)

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