How can I use a string in legend()?

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I have the following string:
Now I want to use this string to produce a legend to my figure. So I use
and get this:
But I would like to have this,
which I got by using the following command:
Tthis is exactly the string Legend copied into the function legend().
How can I use directly the string Legend, without copying it to the function legend()?
Edit: I forgot the following code sniplet:
p=zeros(2*length(HG),1);
hold on;
for iter2 = 1:length(HG)
p(2*iter2-1)=plot(freq,real(n(:,iter2)), 'color', cc(iter2,:));
p(2*iter2)= plot(freq,imag(n(:,iter2)),'--', 'color', cc(iter2,:));
end
I use the variable p to skip all dotted lines in the legend.
  3 个评论
Marcel345614
Marcel345614 2020-10-26
Because I build the Legend-string and want to use it now. This is how I build it:
values=1:2:(2*length(HG)); %only the solid line should have a legend
Legend1=strcat('[',sprintf('p(%d) ',values),']',',');
Legend2=cell(length(HG),1);
quote=char(39);
for iter3=1:length(HG)
if iter3<length(HG)
Legend2{iter3}=strcat(quote,'HS+HG=', num2str(HS(iter3)),'+',num2str(HG(iter3)),quote,',');
else
Legend2{iter3}=strcat(quote,'HS+HG=', num2str(HS(iter3)),'+',num2str(HG(iter3)),quote);
end
end
Legend3=string(strjoin(Legend2));
Legend=strcat(Legend1,'{',Legend3,'}');

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-10-26
Although Walter's comment already shows the problems with eval(), in case you still want to use the current method, then the closest you can get is something like this
fig = figure()
hold on
p(1) = plot(rand(1,10))
p(2) = plot(rand(1,10))
Legend_str1 = "[p(1) p(2)]";
Legend_str2 = "{'ABC', 'DEF'}";
legend(eval(Legend_str1), eval(Legend_str2))

更多回答(1 个)

Alan Stevens
Alan Stevens 2020-10-26
You could use
Legend = ['HS+HG = 0.5+5' ;'HS+HG = 1+5'];
legend(Legend)
But make sure there are the same number of characters (including spaces) in both strings.
  2 个评论
Ameer Hamza
Ameer Hamza 2020-10-26
Following alternatives does not require that character arrays have equal lengths.
Legend = {'HS+HG=0.5+5';'HS+HG=1+5'};
legend(Legend)
or
Legend = ["HS+HG=0.5+5";"HS+HG=1+5"];
legend(Legend)

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