more non-singleton rhs dimensions

I am getting an error here but I am not sure why.
I am trying to create a 1x5 matrix for the 5 c answers using the 5 t values in that matrix.
Thanks

4 个评论

Your screen shot shows some licensing page.
In any case please explain your question in words rather than a screen shot. The code button on the MATLAB answers toolbar allows you to paste in code and have it nicely formatted as in the MATLAB editor
Sorry I attatched the wrong screenshot this is the correct one
Thanks
Copy and past the actual code rather than an image of it, then highlight all of it and use the ‘Insert a line of code’ button to format it cortrectly.
x = (0:1:100)'; 'metres'
Ex = 0.02; 'm^2/s'
m = 1;
u = 0.5; 'm/s'
c = zeros(1,5);
t = [30, 60, 90, 120, 150];
for t = (1:5)
c(1,t) = (m ./ (sqrt(4.*pi.*Ex.*t))).* exp(-((x - u.*t).^2)./(4.*Ex.*t));
end

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 采纳的回答

I'm thinking that you want to loop through your t values. You first assign t to the vector [30,60,90,120,150] but then reassign it in your for loop to (1:5) or [1 2 3 4 5]. You instead need to index your values of t inside of your loop something like
x = (0:1:100)'
Ex = 0.02
m = 1
u = 0.5
c = zeros(101,5)
t = [30,60,90,120,150];
for k = 1:5
c(:,k) = m/sqrt(4*pi*Ex*t(k))*exp(-(x-u*t(k)).^2)./(4*Ex*t(k))
end

2 个评论

Note that the ".*" are only needed for element by element multiplication. You don't need that when you multiply scalars times vectors. Also I think you were trying to put in comments for the units. To do that you need to proceed them with a % sign e.g
Ex = 0.02; % m^2/s
Cheers this has worked thanks for the help.

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更多回答(1 个)

Matthew Gilroy
Matthew Gilroy 2020-10-26
Sorry I attatched the wrong screenshot this is the correct one
Thanks

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