How to convert a vector of integers to a vector of characters?

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Michael
Michael 2013-2-9
Hi - I have a vector of ints, typically 0/1, like this:
[0 0 0 0 1 0 0 0 0 1]
and I want to get this:
['0' '0' '0' '0' '1' '0' '0' '0' '0' '1']
But I cannot figure it out for the life of me. I'm sure it's simple. Thanks for your time and help.

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采纳的回答

James Tursa
James Tursa 2013-2-10
Another method for single digits:
A = [0 0 0 0 1 0 0 0 0 1];
B = char(A+'0');

更多回答（3 个）

Wayne King
Wayne King 2013-2-9
编辑：Wayne King 2013-2-9
A = [0 0 0 0 1 0 0 0 0 1];
B = num2str(A);
Now B is a vector of characters
  2 个评论
Michael
Michael 2013-2-9
Hi Wayne -- I knew of num2str and tried that, but it turns out you're right. But what I figured out was that it was the extra spaces in the result of num2str that was throwing me off. i.e. num2str([0 0 0 0 0]) = '0 0 0 0 0', which is length 9 or something (but not 5). I removed the spaces from the result of num2str and it worked great. Thanks for the help.

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Azzi Abdelmalek
Azzi Abdelmalek 2013-2-9
编辑：Azzi Abdelmalek 2013-2-9
a = [0 0 0 0 1 0 0 0 0 1];
y=arrayfun(@(x) cellstr(num2str(x)),a)
% To get any character
y{4} % for e.g
Jan
Jan 2013-2-10
编辑：Jan 2013-2-10
Instead of removing the spaces from the output of num2str, you can create string without spaces directly:
a = [0 0 0 0 1 0 0 0 0 1];
s = sprintf('%d', a);
Another fast but more strange method is:
s = char('0' + a);

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