Subtracting 2 cells in an array

1 次查看(过去 30 天)
Given:
A=[1,3,5,2,6,1];
Is there a function where I can get a difference of first and following cell in above matrix?
For example, output should be = 1-3, 3-5, 5-2,2-6,6-1 = -2,-2,3,-4,5
Finally, is there a way to sum the entire value in the matrix?
Thanks

采纳的回答

Stephen23
Stephen23 2020-10-28
>> -diff(A)
ans =
-2 -2 3 -4 5
>> sum(-diff(A))
ans =
0
  3 个评论
Stephen23
Stephen23 2020-10-28
编辑:Stephen23 2020-10-28
"could you please explain why u put negative sign before diff?"
Because a-b == -(b-a)
In your question you specified that you wanted "...output should be = 1-3...", which is A(1)-A(2). By definition diff returns A(2)-A(1), but simply negating that gives what you asked for: A(1)-A(2) == -(A(2)-A(1))
Another option would be to use indexing and subtraction (but is likely to be less efficient than diff):
>> A = [1,3,5,2,6,1];
>> A(1:end-1)-A(2:end)
ans =
-2 -2 3 -4 5
>> -diff(A)
ans =
-2 -2 3 -4 5

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Numerical Integration and Differentiation 的更多信息

标签

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by