Extract data from a csv file in Matlab
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Hello,
I am trying to open csv file in Matlab (2020) and extract the data, then put the first column of the data in three columns, year, month day hour.
The data in the csv file attached.
I am using the code below but it is not working. It extracts columns with NaN values. Could you please help me with this? Thanks
fileID = fopen('AberSARAHsolar30deg0deg2012.csv','rt')
C=textscan(fileID,'%s %s %s %s %s %s %s %s ','delimiter',',');
fclose(fileID)
%EXTRACT
time =C{1}(2:end);
Gizero = str2double(C{2}(2:end));
T2m=str2double(C{4}(2:end));
WS10m = str2double(C{5}(2:end));
Githirty =str2double(C{8}(2:end));
%EXTRACT TEXT TO YEAR MONTH DAY HOUR
formatIn ='yyyy-mm-dd hh';
DATETIME=datevec(time,formatIn);
YMDH=DATETIME(:,1:4);
1 个评论
dpb
2020-10-28
Use readtable instead...
Convert the time string to datetime
回答（1 个）
Walter Roberson
2020-10-28
formatIn ='yyyymmdd:HHMM';
It is questionable as to whether that is the correct format, however. Each of the entries ends in 11 . It is not impossible that each of them was taken at exactly 11 minutes after each hour, but it would be uncommon.
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2020-10-28
2020-10-28
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