How to fix it.

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Nisar Ahmed
Nisar Ahmed 2020-10-28
评论: Nisar Ahmed 2020-10-28
wav dimentions are
wav = 5001*1
and I want to change it as wav = 5001*5
How I can reshape it?

采纳的回答

Steven Lord
Steven Lord 2020-10-28
So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?
Make duplicate copies?
x = (1:6).'
y = repmat(x, 1, 5)
Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.
x = (1:6).'
y = x + (0:10:40)
Pad with 0 values or with random data?
x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]
Something else? If so, please explain in detail how you want to generate the additional values.
  3 个评论
Elijah McNeil
Elijah McNeil 2020-10-28
His code does that, Just write this.
x = (1:5000).';
wav = repmat(x, 1, 5).
Nisar Ahmed
Nisar Ahmed 2020-10-28
Elijah McNeil, thanks dear, Now it is working

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更多回答(1 个)

Elijah McNeil
Elijah McNeil 2020-10-28
编辑:Elijah McNeil 2020-10-28
This should work
wav = 5001*1
wav = wav*5
  5 个评论
Elijah McNeil
Elijah McNeil 2020-10-28
Wait 5000 rows and 1 column?
Nisar Ahmed
Nisar Ahmed 2020-10-28
5000 rows and 5 columns, each column is duplicate of other.

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