How to fix it.
显示 更早的评论
wav dimentions are
wav = 5001*1
and I want to change it as wav = 5001*5
How I can reshape it?
采纳的回答
Steven Lord
2020-10-28
So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?
Make duplicate copies?
x = (1:6).'
y = repmat(x, 1, 5)
Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.
x = (1:6).'
y = x + (0:10:40)
Pad with 0 values or with random data?
x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]
Something else? If so, please explain in detail how you want to generate the additional values.
3 个评论
Nisar Ahmed
2020-10-28
Elijah McNeil
2020-10-28
His code does that, Just write this.
x = (1:5000).';
wav = repmat(x, 1, 5).
Nisar Ahmed
2020-10-28
更多回答（1 个）
Elijah McNeil
2020-10-28
编辑：Elijah McNeil
2020-10-28
This should work
wav = 5001*1
wav = wav*5
5 个评论
Nisar Ahmed
2020-10-28
Elijah McNeil
2020-10-28
编辑：Elijah McNeil
2020-10-28
OK, you can't do that unless wav has 5 values. Example:
wav = [5000; 6000;7000; 8000; 9000] % that equals 1 column and 5 rows
wav = wav' % that creates 5 columns and 1 row
reshape(wav,1,5) % this also creates 5 columns and 1 row
Nisar Ahmed
2020-10-28
Elijah McNeil
2020-10-28
Wait 5000 rows and 1 column?
Nisar Ahmed
2020-10-28
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